## Volume Occupied By 1 Molecule Of Water Is Volume Occupied By 1 Molecule Of Water Is. Where n a is avogadro number. 1 mole of water = 6.022 x 10 23 molecules of water, so 55.5 moles of water = 55.5 x 6.022 x 10 23 = 3.34 x 10 25 molecules of water. the density of water is 1g ml what is the volume occupied by 1 molecule from brainly.in

1cm 3=1gm of h 2 o= 181 mol of h 2 o= 181 ×6×10 23 molecules of h 2 o⇒1cm 3 has 31 ×10 23 molecules of h 2 o∴ volume of 1 molecule of h 2 o= 31 ×10 231 cm 3=3×10 −23cm 3hence, the correct option is a. 3.34 x 10 25 molecules of water = 1 litre, Don’t get confused why we considered the value of avogadro’s number.

### = 3 X 10⁻²³ Cm³.

Vm = 18 cm 3 /mol. The number of moles in 1 litre = 1000 / 18.02 = 55.5 moles. 1 mole of water = 6.022 x 10^23 molecules of water, so 55.5 moles of water = 55.5 x 6.022 x 10^23 = 3.34 x 10^25 molecules of water.

### 1 Mole Of Water = 6.022 X 10 23 Molecules Of Water, So 55.5 Moles Of Water = 55.5 X 6.022 X 10 23 = 3.34 X 10 25 Molecules Of Water.

Don’t get confused why we considered the value of avogadro’s number. ∴ molar volume (vm) = m/ρ. 3.34 x 10 25 molecules of water = 1 litre,

### ∴ Volume Of 1 Molecule Of Water = V M /N A.

Density of water (ρ) = 1g/cm 3. =1 gram/ 1 gram cm⁻³ = 1 cm³. Molar mass of water = 18 g / mol.

### In The Last, We Can Say That The Volume Occupied By One Molecule Of Water Is 3.0 × 10 − 23 Cc.

Therefore, volume of 1 molecule of water = v m /n. Volume occupied by one molecule of water is? So, the volume of 1 molecule of water = 18/ (6.023 × 10 − 23) volume of 1 molecule of water = 3.0 × 10 − 23 cc.

### (At Wt Of H *2 + At Wt Of Oxygen = 18) Volume Occupied By 1 Molecules Of Water = (18 / (6.02 X 10²³)) Cm³.

V m = 18 cm 3 /mol. Where n is avogadro number. The gram molecular mass of water is 18.02.